Integrand size = 22, antiderivative size = 98 \[ \int \frac {\left (a+b x^2\right )^p \left (c+d x^2\right )^q}{x^3} \, dx=\frac {b \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )^q \left (\frac {b \left (c+d x^2\right )}{b c-a d}\right )^{-q} \operatorname {AppellF1}\left (1+p,-q,2,2+p,-\frac {d \left (a+b x^2\right )}{b c-a d},\frac {a+b x^2}{a}\right )}{2 a^2 (1+p)} \]
[Out]
Time = 0.06 (sec) , antiderivative size = 98, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.136, Rules used = {457, 142, 141} \[ \int \frac {\left (a+b x^2\right )^p \left (c+d x^2\right )^q}{x^3} \, dx=\frac {b \left (a+b x^2\right )^{p+1} \left (c+d x^2\right )^q \left (\frac {b \left (c+d x^2\right )}{b c-a d}\right )^{-q} \operatorname {AppellF1}\left (p+1,-q,2,p+2,-\frac {d \left (b x^2+a\right )}{b c-a d},\frac {b x^2+a}{a}\right )}{2 a^2 (p+1)} \]
[In]
[Out]
Rule 141
Rule 142
Rule 457
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \text {Subst}\left (\int \frac {(a+b x)^p (c+d x)^q}{x^2} \, dx,x,x^2\right ) \\ & = \frac {1}{2} \left (\left (c+d x^2\right )^q \left (\frac {b \left (c+d x^2\right )}{b c-a d}\right )^{-q}\right ) \text {Subst}\left (\int \frac {(a+b x)^p \left (\frac {b c}{b c-a d}+\frac {b d x}{b c-a d}\right )^q}{x^2} \, dx,x,x^2\right ) \\ & = \frac {b \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )^q \left (\frac {b \left (c+d x^2\right )}{b c-a d}\right )^{-q} F_1\left (1+p;-q,2;2+p;-\frac {d \left (a+b x^2\right )}{b c-a d},\frac {a+b x^2}{a}\right )}{2 a^2 (1+p)} \\ \end{align*}
Time = 0.08 (sec) , antiderivative size = 100, normalized size of antiderivative = 1.02 \[ \int \frac {\left (a+b x^2\right )^p \left (c+d x^2\right )^q}{x^3} \, dx=\frac {\left (1+\frac {a}{b x^2}\right )^{-p} \left (1+\frac {c}{d x^2}\right )^{-q} \left (a+b x^2\right )^p \left (c+d x^2\right )^q \operatorname {AppellF1}\left (1-p-q,-p,-q,2-p-q,-\frac {a}{b x^2},-\frac {c}{d x^2}\right )}{2 (-1+p+q) x^2} \]
[In]
[Out]
\[\int \frac {\left (b \,x^{2}+a \right )^{p} \left (d \,x^{2}+c \right )^{q}}{x^{3}}d x\]
[In]
[Out]
\[ \int \frac {\left (a+b x^2\right )^p \left (c+d x^2\right )^q}{x^3} \, dx=\int { \frac {{\left (b x^{2} + a\right )}^{p} {\left (d x^{2} + c\right )}^{q}}{x^{3}} \,d x } \]
[In]
[Out]
Timed out. \[ \int \frac {\left (a+b x^2\right )^p \left (c+d x^2\right )^q}{x^3} \, dx=\text {Timed out} \]
[In]
[Out]
\[ \int \frac {\left (a+b x^2\right )^p \left (c+d x^2\right )^q}{x^3} \, dx=\int { \frac {{\left (b x^{2} + a\right )}^{p} {\left (d x^{2} + c\right )}^{q}}{x^{3}} \,d x } \]
[In]
[Out]
\[ \int \frac {\left (a+b x^2\right )^p \left (c+d x^2\right )^q}{x^3} \, dx=\int { \frac {{\left (b x^{2} + a\right )}^{p} {\left (d x^{2} + c\right )}^{q}}{x^{3}} \,d x } \]
[In]
[Out]
Timed out. \[ \int \frac {\left (a+b x^2\right )^p \left (c+d x^2\right )^q}{x^3} \, dx=\int \frac {{\left (b\,x^2+a\right )}^p\,{\left (d\,x^2+c\right )}^q}{x^3} \,d x \]
[In]
[Out]